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b^2-17b+10=0
a = 1; b = -17; c = +10;
Δ = b2-4ac
Δ = -172-4·1·10
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{249}}{2*1}=\frac{17-\sqrt{249}}{2} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{249}}{2*1}=\frac{17+\sqrt{249}}{2} $
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